Question 1

1. A rubber ball is dropped from a height of 15 meters. On each rebound, it rises 2/3 of the height from which it last fell. Find the distance traversed by the ball before it comes to rest. The geometric progression occurs after the first rebound.

A. 96 m

B. 85 m

C. 100 m

D. 75 m

Solution:

It is an infinite geometric series problem that starts after the first rebound. The Formula used is:

Where:

S = sum of the geometric progression

a = starting number

r = common ratio

The result is multiplied by 2 since the ball must travel upwards and downwards.

And finally, the initial drop of the ball, which is 15 meters is added to the result which gives: