Monday, April 23, 2012

Question 3


3. Two students were solving a problem that would reduce it to a quadratic equation. The first student committed an error in the constant term and found the roots to be 5 and 7 while the second student made an error in the first degree term and gave the roots as 2 and 16. If you were to check their solutions, the right equation is:

A. X2 + 12X + 35 = 0
B. X2 + 7X -14 = 0
C. X2 + 18X +32 = 0
D. X2 - 12X +32 = 0

Solution:

1st student’s equation: 

2nd student’s equation:

Therefore, the right equation is :  

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5 comments:

  1. UnknownAugust 1, 2016 at 9:10 AM

    Why use negative instead of positive?

    Example is (x-5)(x-7)
    Why not (x+5)(x+7)

    ReplyDelete
  2. UnknownAugust 1, 2016 at 9:22 AM

    Why use negative instead of positive?

    Example is (x-5)(x-7)
    Why not (x+5)(x+7)

    ReplyDelete
    Replies
    1. mBs.nEwBie™November 29, 2016 at 12:01 AM

      the roots would be negative if you use x+5 x+7

      Delete
    2. UnknownMarch 4, 2018 at 9:59 PM

      x=5 , x-5=0 ,x=7,x-7=0, then (x-5)(x-7) factoring

      Delete
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